Javascript Homework Help

**Jeff** · 04-07-2008, 01:02 AM

I am trying to create a function to take the average of a set of numbers that the user enters. I am not having much luck

PHP Code:


<html>
<head>
<script language="JavaScript" type="text/javascript">
    function getAvg(howmany) {
        for (i=0;i<howmany;i++)    {
            var num = prompt("Please enter the number", "")
            var total += num
            var avg = total / howmany
                    }
    return(avg)
                }

</script>
</head>
<body>
<script language="JavaScript" type="text/javascript">
var amount  = prompt("Please enter the amount of numbers you wish to average", "")
getAvg(amount)
</script>
</body>
</html>

**vaughan** · 04-07-2008, 04:20 AM

Wait a few hours and I'll ask my guru if he can help.

**Jeff** · 04-07-2008, 04:34 AM

Thanks, I'll definitely be looking. I spent hours on this at work tonight. It is so frustrating.

**vaughan** · 04-07-2008, 07:44 AM

Michael replying~
You don't need to declare variables with the 'var'. Javascript is annoying because if it gets any kind of error it makes the whole thing not work.

I had something like this;

PHP Code:


<html>
<head>
<script language="JavaScript" type="text/javascript">
    function getAvg() {
    amount = prompt("Please enter the amount of numbers you wish to average", "")
        num = 0
    total = 0
    avg = 0


for (i=0;i<amount;i++)    {
            num = prompt("Please enter the number", "")
            total += num
                    }
    avg = total / amount
    document.write('Average is: ' + avg)
    return(avg)
    
                }

</script>
</head>
<body>
<script language="JavaScript" type="text/javascript">
getAvg();

</script>
</body>
</html>

but I think the algorithm is wrong,

. I havent really sat down to work it all out properly though.. Good luck with it anyway.
-M

**Empty_5oul** · 04-07-2008, 10:17 PM

pretty much you need
num = parseInt(num)
in the for loop otherwise it assumes its a string and concatenates the input in a string.

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